Second Law of Motion

Write down the formula of momentum.

What is the mass of earth?

In how much time an object having mass of $100 \mathrm{kg}$ will speed up from $5 {\mathrm{ms}}^{-1} \mathrm{to} 10 {\mathrm{ms}}^{-1}$ if  $500 \mathrm{N}$ force will be applied to it

In CGS system $1 \mathrm{N}$ is equal to _____.

When we apply a force of $1 \mathrm{N}$, we can hold a body whose mass is approximately equal to

The momentum of a body of mass $5 \mathrm{kg}$ is $15 \mathrm{kg} \mathrm{m}/\mathrm{s}$ . Its kinetic energy is

The change in momentum of a body in$0.01 \mathrm{s}$ is $10 \mathrm{kg} {\mathrm{ms}}^{-1}$. The force acting on it is

If an object of mass $2.5 \mathrm{kg}$ experience a force of $5 \mathrm{N}$, the acceleration produced by it is.

Figure shows four blocks that are pulled along a smooth horizontal surface. The masses of the blocks and tension in one cord are given. The pulling force $F$ is

How many dynes are there in $4 \mathrm{N}$?

Assertion: We should always wear a seat belt while travelling in a car.

Reason: Seat belt prevents us from falling forward due to inertia when sudden brakes are applied.

A loaded lorry of mass $1200 \mathrm{kg}$ moves with a velocity of $12 \mathrm{m} {\mathrm{s}}^{-1}$. Its velocity becomes $10 \mathrm{m} {\mathrm{s}}^{-1}$ after $5 \mathrm{s}$. What is the rate of change of momentum?

A loaded lorry of mass $1200 \mathrm{kg}$ moves with a velocity of $12 \mathrm{m} {\mathrm{s}}^{-1}$. Its velocity becomes $10 \mathrm{m} {\mathrm{s}}^{-1}$ after $5 \mathrm{s}$. Calculate the change in momentum.

A loaded lorry of mass $1200 \mathrm{kg}$ moves with a velocity of $12 \mathrm{m} {\mathrm{s}}^{-1}$. Its velocity becomes $10 \mathrm{m} {\mathrm{s}}^{-1}$ after $5 \mathrm{s}$. The final momentum will be:

A loaded lorry of mass $1200 \mathrm{kg}$ moves with a velocity of $12 \mathrm{m} {\mathrm{s}}^{-1}$. Its velocity becomes $10 \mathrm{m} {\mathrm{s}}^{-1}$ after $5 \mathrm{s}$. The initial momentum will be:

A car rolls down a hill with an acceleration of $1.5 \mathrm{m}/{\mathrm{s}}^2$. If the mass of the car is $900 \mathrm{kg}$, calculate the unbalanced force that acts on the car.

The momentum is the product of mass and _____.

When a body travels at uniform velocity, its momentum changes by _____ $\mathrm{kg} \mathrm{m} {\mathrm{s}}^{-1}$.

In the equation $F=kma$, $k$ will become one for one unit of force. One unit of force is also equal to one _____.

Consider the equation $F=kma$. The unit of force is so chosen that the value of the constant, $k$ becomes _____.